48x^2=2x^2+4x

Solution for 48x^2=2x^2+4x equation:

48x^2=2x^2+4x

We move all terms to the left:

48x^2-(2x^2+4x)=0

We get rid of parentheses

48x^2-2x^2-4x=0

We add all the numbers together, and all the variables

46x^2-4x=0

a = 46; b = -4; c = 0;
Δ = b2-4ac
Δ = -42-4·46·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4}{2*46}=\frac{0}{92}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4}{2*46}=\frac{8}{92}
=2/23
$